Consider a separation performed a 400 long open tubular col with a 050 mm diamet

Question

Consider a separation performed a 400 long open tubular col with a 050 mm diameter, an a 20 thick stationary phase, Compound A eluted at 12.58 min, compound at 13.17 min, and the unretained solvent eluted at 1.115 min. are the adusted retention times, and retention factors, for oompoundsAandB? min min What is the relative retention, a for this separation? scroll down to answer the rest of this question. The width at half-height, wh2, of the peak for compounds A and Bare 0,122 min compound respectively, Find the number of theoretical plates, N and plate height, each op viors check Answer Next careers prwacy po ty terms of use contact a la

Explanation / Answer

Adjusted retention time (tR')=time spent by solute in the stationary phase or

retention time(tR)-elution time of unretained peak(tm)

trA'=12.58min-1.115min=11.465min

trB'=13.17min-1.115min=12.05min

k=time spent by analyte in stationary phase/time spent by the analyte in the mobile phase=tr-t0/t0

kA=12.58-1.115/1.115=11.465/1.115=10.282

kB=13.17-1.115/1.115=12.05/1.115=10.807

relative retention=alpha/=trB'/trA'=12.05/11.465=1.05

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