The Co-60 radiation source was manufactured in January, 2016. If the counts/30s
ID: 524159 • Letter: T
Question
The Co-60 radiation source was manufactured in January, 2016. If the counts/30s for the Co-60 source at a distance of 0cm from the counter was 3,300 when new, calculate the approximate half-life for Co-60.ln(Nt/No)=-k/t t1/2=0.693/k
When comparing my result to the actual half life of Co-60, I realize I have terribly messed up somewhere! Help!
Please show all steps in any math. Thank you!
Ill. Estimation of Source Half-Lives 1. The Co-60 radiation source was manufactured in January, 2016. lf the counts/30 s for the Co-60 source at a distance of 0 cm from the counter was 3,300 when new, calculate the approximate half-life for Co-60. O, 693 In (Nt/No) kt t1/2 0.693 k In 2002/330) -Kloso
Explanation / Answer
Data given:
At t=0, No = 3300
At t=30s, Nt = 2902
Putting values in the eqn:
ln(2902/3300) = -k*30
k = 0.004284
Next, putting this value in the following eqn:
t1/2 = 0.693/k
S, t1/2 = 0.693/0.004284 = 161.764 s = 2.696 minutes