Carly the chemistry student performs an experiment with vinegar (active ingre 2.

Question

Carly the chemistry student performs an experiment with vinegar (active ingre 2. Carly the chemistry student performs an experiment with vinegar (active ingredient acetic acid, CHvcooH) and baking soda (NaHcol. Her professor asks her to place varying amounts of baking soda and vinegar into sealable plastic bags, quickly seal the bags, and observe the reaction. The balanced chemical equation for the reaction is given here. a) Use limiting reagent calculations to fill in the following table. Please show your work Trial Baking. Vinegar (5% T Amount of Amount of Limiting Amount of conformed acetic acid) Co2 (mol) if CO2 (mol) if reactant soda (mo) baking soda vinegar limiting limiting 10. mL. A 0.25 g 8.0 mL 0.75 g 5.0 mL 1.5 g b) Which Ziploc bag will inflate the most?

Explanation / Answer

When NaHCO3 is limiting

a) Trial A

moles NaHCO3 = 0.25/84 = 0.003 mol

moles CO2 formed = 0.003 mol

b) Trial B

moles NaHCO3 = 0.75/84 = 0.009 mol

moles CO2 formed = 0.009 mol

c) Trial C

moles NaHCO3 = 1.5/84 = 0.018 mol

moles CO2 formed = 0.018 mol

when vinegar is limiting

molarity of vinegars solution = 5/60 x 0.1 = 0.833 M

a) Trial A

moles acetic acid = 10 x 0.833 = 8.33 mol

moles CO2 formed = 8.33 mol

b) Trial B

moles acetic acid = 8 x 0.833 = 6.664 mol

moles CO2 formed = 6.664 mol

c) Trial C

moles acetic acid = 5 x 0.833 = 4.165 mol

moles CO2 formed = 4.165 mol

Limiting reactant in all is NaHCO3

So,

moles of CO2 formed = moles of NaHCO3 added

c) The one which would have greatest amount of CO2 formed would inflate the most. So Trial C would inflate most

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