If the pressure inside a container is 152.48KPa at 29.34 degree C, what will be
ID: 526264 • Letter: I
Question
If the pressure inside a container is 152.48KPa at 29.34 degree C, what will be the pressure at 193.78 degree C? ___ If a gas has a volume of 61.34 qts at 98.44 degree C, at what temperature, in degree C, will the volume be 488.48qts? ___ If the pressure in a can is 26.47psi at 92.37 degree C, at what temperature, in degree C, would the pressure be 2.927atm? ___ If the volume of a gas at STP is 78.34L, what will be its volume if we decrease the temperature by 57.86 degree C? ___ If a gas has a volume of 763.48mL at 56.27inHg, what would be its volume at if we increase the pressure by 20.36KPa? ___Explanation / Answer
Given
Pressure P1 = 152.48 KPa
Temperature T1 = 29.34 C = 302.34 K
Temperature T2 = 193.78 C = 466.78 K
PV = nRT => P/T = nR/V
P1 / T1 = P2 / T2
152.48 KPa / 302.34 K = P2 / 466.78 K
P2 = 235.4 KPa Answer
Volume V1 = 61.34 sqts = 58.13 L
Temperature T1 = 98.44 C = 371.44 K
Temperature T2 = ?
Volume V2 = 488.48 sqts = 462.27 L
PV = nRT
V / T = nR/P
V1 / T1 = V2 / T2
58.13 L / 371.44 K = 462.27 L / T2
T2 = 2953 K = 2680 K