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ID: 526512 • Letter: C

Question

Can someone answer this question with the reference? Please try to give the link of the source if applicable. It's the second time i'm posting this question. So, please try to give the correct answer.

(5) In the photosynthetic reaction center, the o biomolecule in which solar energy conversion takes place, an unusual closely packed arrangement of two chlorophyll molecules, called the special pair', absorbs light at 870 mm (ot coincidentally the solar emission maximum). Chlorophylls look like hemes but are designed to better do photochemistry: a How much energy, in Kcalmol, is this (E hv)? b This photon absorption causes an electron to be transferred from the special pair to another, single d molecule of chlorophyll. the transfommation o RA from light energy to chemical energy is 100% efficient and it actually is very nearly so) what is the minimum reduction potential that the accepter cholorphyll can have with respect to the donor? molecules very close together at the center of the protein). What residues are involved in binding this pair (int, the chlorophylls are called BLC in the structure, so you can select them separately with 'select chlor, resn BCL) and then manipulate them with the buttons on the right that are under the chlor' header.) Are any of these molecules involved in hydrogen bonding to the special pair cofactors If so, list them, specifying the donor and acceptor groups

Explanation / Answer

Let me help you with the first part.

v= frequency (in sec-1)
h=plancks constant=6.626*10-34J s
c= speed of light= 3*10-8 m/s

wavelength= c/v
v=(3*10-8 m/s)/ 870*10-9m
v=3.44*1014 s-1

Energy, E=hv
E= (6.62*10-34 J s)*3.44*1014 s-1
E= 22.82*10-20 J

Multiply by Avagadros number to get Joules per mole

E= (22.82*10-20 J)*6.023*1023 mol-1
E= 137.44*103 J mol-1

Divide by 1000 to get KJ mol-1

E=137.44 KJ mol-1

To convert to Kcal divide by 4,18

E= 32.84 Kcal mol-1

Hope this helps.