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Identify the relationship between the following two structures. A. Enantiomers B

ID: 527348 • Letter: I

Question

Identify the relationship between the following two structures. A. Enantiomers B. Identical C. Neither Which of the following is the correct structure for the compound (R)2-pentanol? What is the percentage of the R enantiomer in a sample of carvone that has a specific rotation of +30, given that the specific rotation of (R)-carvone is -61? A. 26% B. 51% C. 49% D. 75% Which of the following is a substitution reaction? What is the nucleophile in the following reaction? What is the electrophile in the following reaction? Which of the following is the correct IUPAC name of the following structure? A. (S) 2-Bromo-4, 5-dimethylheptane B. (R)-2-Bromo-4.5-dimethylheptane C. 3, 4-Dimethyl-6-bromoheptane D. 2-Bromo-4-methylhexane Which of the following is the correct structure for a compound with the IUPAC name of (R)-2-fluorobutane? Which of the following shows the correct arrow for loss of a bromide leaving group? Which of the following is the rate law for the following S_N1 reaction? A. Rate = k[tert-Butyl bromide] B. Rate = k[HOCH3] C. Rate = k[HOCH_3][tert-Butyl bromide] D. Rate = k[HOCH3]^2

Explanation / Answer

(35)

(B) There is no chiral carbon, so, they both are identical to one another.

(36) (C) i sthe [R]-2-pentanol

(37)

(38) (B) is the substitution reaction. Because the Cl atom is being substituted for -OCH3

(39) (A) SH2 is nucleophile. Becuase S has two lone pairs, with which sulphur attacks the electrophilic carbon.

(40) (B) Is the electrophile. Becuase of more electronegativity of I, it attracts the bond pair of electrons towards itself, creacting a partial positive charge on Carbon, making it electrophile.

(41) (A) is correct IUPAC name of the given compund

(42) (D)

(43) (A) Because of Br is more eletronegative than carbon, hence while it is leaving the carbon it takes the bond pair of electrons.

(44) (A) IN SN1 mecahnism the slow and rate determining stetp involves only alkyl halide. Hence (A)