CO (g) + H 2 (g) <--> C(s) + H 2 O (g) H = -131 kJ A rigid container holds a mix
ID: 527619 • Letter: C
Question
CO (g) + H2(g) <--> C(s) + H2O (g) H = -131 kJ
A rigid container holds a mixture of graphite pellets (C(s)), H2O(g), CO(g), and H2(g) at equilibrium. State whether the number of moles of CO (g) in the container will increase, decrease, or stay the same after each of the following disturbances is applied to the original mixture. For each case, assume that all other variables remain constant except for the given disturbance. Select the response which includes the best explanation.
b. The temperature of the equilibrium mixture is increased at constant volume.
c. The volume of the container is decreased at constant temperature.
d. The graphite pellets are pulverized.
Explanation / Answer
The disturbances in any system is governed by Le Chatliers principle.
CO (g) + H2(g) <--> C(s) + H2O (g) H = -131 kJ
since
H = -131 kJ is negative reaction is exothermic.
b) If we increase the temperature the reaction shift towards backward direction so as to decrease the effect of increased temperature.Thus no.of moles of CO (g) increases.
c) When volume is decreased, no.of moles/ unit volume increases so system tries to decrease no.of moles by proceeding reaction in forward direction. Thus CO (g) no.of moles decreases.
d) Graphite pellets are pulverised, that means C (s) concentration increases, thus system tries to decrease its effect by proceeding reaction in backward direction. That is no.of.moles of CO (g) increases.