Megajoule (1 million joules) is needed for an industrial process You need to det

Question

Megajoule (1 million joules) is needed for an industrial process You need to determine the carbon footprints the fuel options available. You've narrowed down the choices to oil and natural gas. Given the following information, determine the carbon footprints of each fuel source. Determine the amount of energy you'll need to produce to have 1 Megajoule available for the industrial process. Determine the mass of each fuel required to produce the amounts of energy you found above in problem Calculate the mass of carbon in each of the fuel amounts you found in problem 2) above. Calculate the mass of carbon dioxide that will result from using each of the fuels to provide the required amount of energy At standard temperature and pressure

Explanation / Answer

For Natural gas,

Amount of energy in MJ = 1 / 0.87 = 1.1 MJ

Amount of energy in kJ = 1.1 X 103 kJ

Mass of natural gas = Amount of energy in kJ / Specific Energy in kJ g-1

= 1.1 X 103 kJ / 55.5 kJ g-1

= 19.81 g

Mass of carbon in the fuel = %C X Mass of natural gas

= 0.75 X 19.81 g = 14.86 g

Number of moles of carbon = Mass of carbon in the fuel / Atomic mass of carbon

= 14.86 g / 12.01 g mol-1 = 1.24 mol

We know, 1 mol of carbon gives 1 mol of CO2

Number of moles of CO2 = Number of moles of carbon = 1.24 mol

Mass of CO2 = Number of moles of CO2 X molar mass of CO2

= 1.24 mol X 44.01 g mol-1 = 54.44 g

For Oil,

Amount of energy in MJ = 1 / 0.82 = 1.2 MJ

Amount of energy in kJ = 1.2 X 103 kJ

Mass of oil = Amount of energy in kJ / Specific Energy in kJ g-1

= 1.2 X 103 kJ / 48.0 kJ g-1

= 25.41 g

Mass of carbon in the fuel = %C X Mass of oil

= 0.83 X 25.41 g = 21.09 g

Number of moles of carbon = Mass of carbon in the oil / Atomic mass of carbon

= 21.09 g / 12.01 g mol-1 = 1.76 mol

We know, 1 mol of carbon gives 1 mol of CO2

Number of moles of CO2 = Number of moles of carbon = 1.76 mol

Mass of CO2 = Number of moles of CO2 X molar mass of CO2

= 1.76 mol X 44.01 g mol-1 = 77.27 g

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