1H NMR 13C NMR inert compound (insoluble in h2o, naoh,hcl,h2so4) halide test (no

Question

1H NMR

13C NMR

inert compound (insoluble in h2o, naoh,hcl,h2so4)
halide test (no color --> chloride)
non-aromatic
negative test for 2,4 dinitrophenylhydrazine

ir spectrum

2017/03/14 11atsoe00 0.88 5.06 3.00 ZeroFilngnant 1024 : 49MzEB83 ppm) 56Hz(Q.95 63Hz(106ppm] 4:Hz(1.23ppm) 5: g2 H2(1.37 ppm Hz (1.48 pgm] 7 93Hz (1S7 ppm) 8: 97Hz(1.63 9: 100Hz(1680pm 10: 107 Hz [180ppm 11: 114Hz(1.91 ppm) 12: 115Hz(194ppm) 13:229 Hz (3.84 ppm) 14: 235 Hz(335ppm IS: 241 Hz(405 pome SPPM 4,5PPM 4PPM 3.5PPM 3PPM 2.5 PPM 2 PPM 1.5 PPM 1PPM 0.5PPM 0Pru

Explanation / Answer

There are four peaks in C-13 spectrum

That means there are four C - atoms in chain. Negative dnp test means no carbonyl grp is there. From IR its clear that only C-H grps are present and shows peak near 1500 that could be of N-H. In NMR we have one quartet, one singlet one multiplet and one triplet, but we can never confirm anythn without mass spectra

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---