Consider the following reaction for the next four questions (this is the reactio

Question

Consider the following reaction for the next four questions (this is the reaction of photosynthesis): 6CO_2(g) + 6H_2O(l) rightarrow C_6H_12O_6(s) + 6O_2(g) What is Delta S degree for this process, given the following data? Substance: CO_2(g) H_2O(l) C_6H_12O_6(s) O_2(g) S degree (J/(mol K)): 214 70 212 205 -262 J/(K middot mol) 262 J/(K middot mol) -1287 J/(K middot mol) 133 J/(K middot mol) -133 J/(K middot mol) Given that Delta G degree for the reaction is 2880 kJ/mol at 25 degree C and using the result for the previous problem, what is Delta H degree for this reaction at 25 degree C? -2802 kJ/mol 2802 kJ/mol 2958 kJ/mol 80956 kJ/mol -75196 kJ/mol Given that Delta G degree for the reaction is 2880 kJ at 25 degree C, what is the equilibrium constant for this reaction at 25 degree C? TildeTilde 0 1 infinity .0001 not enough data to calculate K Which one of the following statements would be true for the reaction in the preceding questions? This reaction is favorable (spontaneous) at high temperatures, but unfavorable (non-spontaneous) at lower temperatures. This reaction is favorable (spontaneous) at low temperatures, but unfavorable (non-spontaneous) at higher temperatures. This reaction is unfavorable (non-spontaneous) at all temperatures. This reaction is favorable (spontaneous) at all temperatures.

Explanation / Answer

Ans11 delta S = Sp - Sr

= 212 + 6(205) - 214*6 - 6(70)

delta S = -262 JK-1mol-1

Ans 12 delta G = delta H -T delta S

Delta H = 2880000 + 298*(-262)

delta H = 2802 Kjpermol

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