Consider two genes with the alleles A/a and B/b. If the two genes are 30 m.u. ap
ID: 53135 • Letter: C
Question
Consider two genes with the alleles A/a and B/b. If the two genes are 30 m.u. apart what gametes will an individual with the genotype AB/ab be expected to produce?
a. 35% will contain A and B alleles, 35% will contain a and b alleles, 15 % will contain A and b, and 15% will contain a and B
b. 25% of each of the following allele combinations: A and B, A and b, a and B and a and b
c. 20% will contain A and B alleles, 20% will contain a and b alleles, 30% will contain A and b alleles, and 30% will contain a and B alleles
d. 35% will contain A and b, 35% will contain a and B, 15% will contain A and B, and 15% will contain a and b
e. 30% will contain A and B, 30% will contain a and b, 20% will contain A and b, and 20% will contain a and B.
Explanation / Answer
Answer:
(a) 35% will contain A and B alleles, 35% will contain a and b alleles, 15 % will contain A and b, and 15% will contain a and B
You perform the following cross and are told that the two genes are 30 m.u. apart.
A B/a b x a b/a b
Among their progeny, 30 percent should be recombinant (A b/a b and a B/a b), therefore Ab / ab should represent 1/2 of recombinants or 15%.
and 70 percent should be parental (A B/a b & a b/a b), therefore, A B/a b should represent 1/2 of the parentals or 35%.