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Part A Given the two reactions H2SHS+H+, K 1 = 9.65×10 8 , and HSS2+H+, K 2 = 1.

ID: 531644 • Letter: P

Question

Part A

Given the two reactions

H2SHS+H+,   K1 = 9.65×108, and

HSS2+H+,   K2 = 1.40×1019,

what is the equilibrium constant Kfinal for the following reaction?

S2+2H+H2S

Enter your answer numerically.

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Part B

Given the two reactions

PbCl2Pb2++2Cl,   K3 = 1.78×1010, and

AgClAg++Cl,   K4 = 1.14×104,

what is the equilibrium constant Kfinal for the following reaction?

PbCl2+2Ag+2AgCl+Pb2+

Express your answer numerically.

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Kfinal =

Explanation / Answer

Part A

The given reactions are:

H2S <=====> H+ + HS-; K1 = 9.65*10-8 …..(1)

HS- <=====> H+ + S2-; K2 = 1.40*10-19 …..(2)

The required reaction is

S2- + 2 H+ <=====> H2S ….(3)

Expression (3) obtained by reversing (2) and (1) and adding the reverse equations. The reverse equations are below:

H+ + HS- <=====> H2S; K1’ = 1/K1 = 1/(9.65*10-8) = 1.036*107

S2- + H+ <======> HS-; K2’ = 1/K2 = 1/(1.40*10-19) = 7.143*1018

The overall equilibrium constant is

K = [H2S]/[S2-][H+]2 = {[H2S]/[H+][HS-]}*{[HS-]/[S2-][H+]} = K1’*K2’ = (1.036*107)*(7.143*1018) = 7.400*1025 7.4*1025 (ans)