For the following chemical equation a student reacts 3.75 grams of magnesium (Mg

Question

For the following chemical equation a student reacts 3.75 grams of magnesium (Mg) with 415 mL of 1.25 M HCL. The hydrogen gas is collected over water in an inverted piece of glassware that allows the user to measure the volume of gas produced (eudiometer tube). The position of the eudiometer tube can be adjusted such that the level of liquid inside and outside the tube is the same. The barometric percent in the lab is 755 torr and the room temperature is 23.0 degree C. Assuming that the hydrogen gas is collected at room temperature and the vapor pressure of water at 23.0 degree C is 22.1 torr what is the maximum volume of hydrogen gas that could be collected? If the heat produced by the reaction is 155 kJ what would be the actual volume of hydrogen gas collected (assume the percent yield is the same for all products)? Mg(s) + 2 HCl (aq) rightarrow Mg Cl_2 (aq) + H_2 (g) + 460 kJ Arrange the following in order of increasing radius: K^+ O^2- Al^3+ K, Na^+, Ar

Explanation / Answer

Hiu,

Unable to comprehend the part 1. Could you make it a bit clear.

b) Part 2, the ionic radii depends on number of proton and electron

O2-, Ar, K+ all have 18 electrons, more protons, smaller size. So, o2-> Ar>K+
Na+, Al3+ have 10 electron each so, Na+>Al3+
Uncharged specie have size higher than cation and less than anion for isoelectronics.

Overall O2-> Ar> K> K+>Na+>Al3+

Hope this helps.

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