Hex-1-yne + HCl then H_2O rightarrow a) alcohol b) aldehyde c) ketone d) alkyl h
ID: 537030 • Letter: H
Question
Hex-1-yne + HCl then H_2O rightarrow a) alcohol b) aldehyde c) ketone d) alkyl halide 1-Methylcyclohexene + 1) OsO_4, 2) H_2O_2 rightarrow a) cis 1, 2-idol b) trans 1, 2-diol c) primary alcohol d) carboxylic acid Pent-2-yne + Br_2 (2eq) rightarrow a) monobromoalkane b) dibromoalkane c) tribromoalkane d) tetrabromoalkane 2-Methylhex-2-ene + 1) Hg (OAc)_2, 2) H_2O, 3) NaBH_4 rightarrow a) primary alcohol b) secondary alcohol c) tertiary alcohol d) 1, 2-diol 2-hexyne + H_2 with Lindlar cat. Rightarrow a) cis alkene b) trans alkene c) alkane d) alcoholExplanation / Answer
16. Option (a) is correct answer
1-hexyne reacts with HCl produces 1-chlorohexane which further reacts with water gives an alcohol.
17. Option (a) is correct answer.
1-methylcyclohexene reacts with OsO4 (osmium tetroxide) produces osmate ester which then treats with peroxide gives cis-1,2 –diol and regenerate osmium tetroxide. It’s a hydroxylation of cycloalkene.
18. Option (d) is correct answer
Halogenation of 2 –pentyne gives 2,2,3,3-tetrabromopentane (tetrabromoalkane)
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