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Phosphate buffer On the first pic, need to know questions number 2, please. Seco

ID: 538229 • Letter: P

Question

Phosphate buffer
On the first pic, need to know questions number 2, please.
Second pic: please answer C. A) pH= 7.5 B) pH = 7.5 C) pH NaOH = 13.27 pH HCL = 2.42
POSTLAB DISCUSSION- PHOSPHATE BUFFER This form should be filled out using PEN only. Mistakes should be crossed through with a single line only. Note: all calculations must be shown in lab notebook pages to receive credit TABLE 1: BUFFER ASSIGNMENT (M Concentration Volume (mL) pH 6.a 0.025 TABLE 2: PH RESULTS, MEASURED AND CALCULATED pH phosphate buffer 9,13 buffer+ NaOH 6. 6-40 13,2 2. 2 buffer + HCI DI water + NaOH DI water +HC Calculated Prediction buffer +NaOH buffer + HCI DI water + NaOH DI water+ HCI PH 73 6.3 10.3 S.I . Compare the pH change of your buffered system with that of the unbuffered systems when strong base and strong acid were added? Briefly explain how the buffer is able to maintain its pH. Which of the following is true about buffers? (Circle all that apply.) a· The concentration of a buffer refers to the number of moles of the acid species per liter of solution. 2. Either molarity or number ofmoles can be Either molarity or number of moles can be used in the Henderson-Hasselbalch equation for calculating pH of buffers Buffers are any solution that contains both an acid and a base. TherKaisa constant value associated with the base component of the buffer system. The primary function of buffers is to resist changes in pH, c. c. e·

Explanation / Answer

C)

i) pH for NaOH = 13.27 so pOH= 0.73

NaOH is strong base

So, [OH-]= Concentration of solution= Antilog[-0.73]= 0.186

ii) Now pH for HCl =2.42

HCl is strong acid

So, [H+]= Concentration of solution=Antilog[-2.42]=0.003801