Please help!!! I know NH4OCONH2 is a solid so we don\'t count it when looking fo
ID: 539733 • Letter: P
Question
Please help!!! I know NH4OCONH2 is a solid so we don't count it when looking for equilibrium and I have already tried making 2 separate ice tables and I just can't seem to figure out what method to use (quadratic formula or approximation) and no matter what I try I keep getting insane numbers. Thank you!
At a certain temperature, Kp = 2.9 times 10^-5 for the following reaction: NH_4 OCONH_2 (s) 2 NH_3 (g) + CO_2 (g) In an experiment carried out at this temperature, a certain amount of NH_4 OCONH_2 and 0.500 atm of CO_2 is placed in a container and allowed to come to equilibrium. Calculate the partial pressures of all gases at equilibrium.Explanation / Answer
NH4OCONH2 (s) ----------------> 2 NH3 (g) + CO2 (g)
- 0 0.500 atm
- x 2x 0.5 + x
Kp = P2NH3 x PCO2
2.9 x 10^-5 = (2x)^2 x (0.5 + x)
2.9 x 10^-5 = 4x^2 (0.5 + x)
2.9 x 10^-5 = 2 x^2 + 4x^3
4x^3 + 2x^2 - 2.9 x 10^-5 = 0
x = 3.79 x 10^-3
partial pressure of all gases :
PNH3 = 0.00758 atm
PCO2 = 0.504 atm