I just need problem 3.4-1. Please show all work. Thanks! 3.4.1 The atomic radius
ID: 542055 • Letter: I
Question
I just need problem 3.4-1. Please show all work. Thanks! 3.4.1 The atomic radius of Mn +2 is 0067 nm, while the radius of S-2 is R-O 0.184 nm. What is the c 3.4-2 Prove that a Tit cation would fit loosely in the body-centered sixfold (octahedral) void formed by six O-2 ions 34-3 Calculate the density of BaT1O, given that the atomic weights of each atom in the material are Ba 137.33 g/mole. ture of the compound MnS? Support your answer by appropriate calculations. on face-centers of the Perovskite structure of BaiO, The radi of these ions are Ba2 0.136 nm, 2 and Ti+ 0.068 nm. what unusual property does this loose-fitting +4 ion give rise to? im,Explanation / Answer
Answer 3.4.1)
Given data: Cationic radius of Mn2+ (r) = 0.067 nm & Anionic radius of S2- (R) = 0.184 nm.
Let's find cation-anion radius ratio from this as
Cation-anion radius ratio = (r/R) = 0.067/0.184 = 0.364.
Reference table:
The value 0.364 fits to the row 0.225-0.414 which corresponds to tetrahedral geometry.
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Radius Ratio Coordination number Type of void Example < 0.155 2 Linear 0.155 - 0.225 3 Triangular Planar B2CO3 0.225 - 0.414 4 Tetrahedral ZnS, CuCl 0.414 - 0.732 6 Octahedral NaCl, MgO 0.732 - 1.000 8 Cubic CsCl, NH4Br