Question
All please
The change in the interml y of a system that aes ,50 of eat and thus dos 7,0551 ot 8) 10155 0-1.99-107 D) 5135 -8,155 9)The vabar orst, for lhe re action below is-72 k) when 2 moles ot imr am preduced what I'm, ot heat released whes 1.0 mol of Hie is oed in this reaction A)72 B)044 .72 D) 36 E) 144 0) When a system E i, almas negative. A) gives off heat and has work done on it 5) absorbs heat and does work C gives off heat and does work D) absorbs heat and has work done on it E) none of the above is always negative 11) Given th" data in the table below, non for the reaction is kl Ca(OH)2 + 2H3/a4 Ca(H2 AsO4h2 + 2H2O Substance AHe kimol) Ca(oH)z H3AsO 900,4 H20 85,9 A) -4219 18)-764 C-4519 D-744.9 E)-1304 12) Given the following step reactions, N2(g) +202(g) 2NO2(g) +-66.4k] 2NO (g) + O2(g) 2NO2 (g} -1142 kj 's Law to calculate enthalpy of reaction (AHrxnl where N2(g)·O2(g) produce Nog), as shown below: C) 90.3 D) -47.8 E) 180.6 A)-180.6 B) 47.8
Explanation / Answer
8)
Q = - 2500 J (negative because heat is released)
W = -7655 J (negative because system does work)
use:
U = Q + W
U = (- 2500 J) + (-7655 J)
U = -10155 J
Answer: -10155 J
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