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Please I need quick response! Bonus points ! DETAILS explanation with any equati

ID: 54346 • Letter: P

Question

Please I need quick response! Bonus points ! DETAILS explanation with any equation much apreciated

In an action potentia in myelinated fibers, the conduction velocity is proportional to the diameter of axon (meaning it increases or decreaes in relation to one another). In unmyelinated fibers it is approx. proportional to square root of diameter. With info above, describe benefit of myelination in term of required space when transferingg action potential at a speed given. As axon diameter & distance traveled decreases, at what point would benefit of myelination not apply likely? Based on relationships given above, why is myelination not much useful for axons traveling short distances? Writing relationships from info in this problem will be helpful.

I post this question twice because everytime only one aspect is answered and I need ALL aspects of question answered. Please try answer all questions in this and show me the relationships between all of information provided!!!

Explanation / Answer

Nerve impulse can travel only along the cytoplasm because it is totally dependent on the sodium and potassium channels present in the cytoplasm. In a myelinated sheath, these channels are present only at the node of ranvier. Therefore, the nerve impulse travels much faster, becauses instead of moving , it jumps over from one node to another node. It is a very useful method for long distance transport of nerve impulse.

If axon diameter and distance travels is decreased, there is point where there is no use of myelination left. Myelination serves the purpose of energy conservation. A thick myelin sheath reduces charge leakage. In a thick sheath , charge leakage will occur only at the nodes, while in a unmyelinated sheath charge leakage will occur everywhere.

Now, less distance travel means more nodes of ranvier, and more charge leakage. Apparently the concept of myelination is lost, because now the myelinated neuron is no longer able to conserve the charge.

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