Which of the following expressions correctly sets up the calculation needed to d

Question

Which of the following expressions correctly sets up the calculation needed to determine the number of grams of KCIO3 produced during the reaction of 0.150 moles of Cl2 in excess potassium hydroxide according to the following reaction? 3C12+ 6KOH 5KCI + KCIOg + 3H2 Select one: Oa. 0.150 mol KCIO,3 mol C 1 mol KCIO 1 mol KCIo3 122.548 g KCIO b0.150 mol Cl 1 mol KCO, 122.548 g KCIO3 O . 0.150 mol KCIO3, d 0.150 m ol Clh, ts. 3 mol Cl 1mol KCIOg 3 mol C2,122.548 g KCO 1 mol KCIO31 mol KCIO2 O 3mol Cl 1 mol KCIO 1 mol KCIo, 122.548 g KCIO2

Explanation / Answer

moles of KClO3 formed = (1/3)*moles of Cl2
= 0.150 mol of Cl2 * 1 mol KClO3/3 mol of Cl2

To get mass, we need to multiply it by molar mass
That is multiply above expression by 122.548 g KClO3/1 mol of KClO3

Answer: b

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