Consider the following system at equilibrium where H:-198 kJ, and Kc-345, at 1.1
ID: 544177 • Letter: C
Question
Consider the following system at equilibrium where H:-198 kJ, and Kc-345, at 1.15x103 K. 2S02(g) +02(g)2s0j(g) If the VOLUME of the equilibrium system is suddenly decreased at constant temperature: The value of KcA. increases. B. decreases C. remains the same The value of QA. is greater than Kc B. is equal to K C. is less than Kc The reaction must: A. run in the forward direction to reestablish equilibrium. B. run in the reverse direction to reestablish equilibrium C. remain the same. It is already at equilibrium. The number of moles of O2 will A. increase B. decrease. C. remain the same.Explanation / Answer
1)
Kc depends on Temperature
So, kc will not change
Answer: C
2)
decreasing volume is like increase pressure
so, according to Le Chatelier's principle,
Reaction will try to decrease the pressure
Hence it will move in a direction which have lesser gaseous molecules
Here product has less gaseous molecule
So equilibrium will move to right
So, Qc will be less than Kc
Answer: C
3)
Answer: A
explained above
4)
Answer: B
since reaction is moving in forward direction