CHEM 1211 Lab Manual- Revised 052017 Ideal Gas Law, PV nRT Name Instructor (Unle

Question

CHEM 1211 Lab Manual- Revised 052017 Ideal Gas Law, PV nRT Name Instructor (Unless otherwise noted, 2 pts. for each blank) Molarity of HCI (M) (1pt. each): Volume of HCI (mL): Mass of Mg (gram): *Volume of gas before placing in Section Partner Data, Trial 1 Data, Trial 2 1a.aml20.Onl 0.044 0.04kg Equalization Chamber (mL) (1 pt.) (This value NOT used in calculations below) Volume of gas after placing Lu ml 46 o ml in Equalization Chamber (mL): Barometrie Pressure (mm Hg): 38.2 138 2 wnHp 22.6C 2222c Temperature (°C) Write the balanced overall equation for the reaction of magnesium and HCl to form hydrogen gas and the magnesium salt (2 pts): Mole of Mg reacted Mole of H2 formed (based on the stoichiometric equation for the reaction) Vapor Pressure of water from curve in mm Hg: Pressure of H2 from Dalton's Law in mmHg: Pressure of H2 in atm Volume of H2 in liter (Using volume measured in Equalization Chamber) Temperature in Kelvin Calculation of R (6 pts. each) Percent error Average R = 63

Explanation / Answer

Trial 1.

a)

mol of Mg = mass/MW = 0.044/24.3= 0.001810

ratio is 1:1 so mol of Mg = mol of H2

mol of H2 = 0.001810

b)

vpaor pressure fro 22°C --> 19.8 mm Hg

c)

pressure of H2 --> Ptotal = Pgas + Pvapor

Pgas = PTotal - Pvapor

Pgas = 738.2- 19.8 = 718.4 mm Hg

d)

pressure in Atm

1 atm = 760 mm Hg

Pgas = 718.4/760 = 0.945263 atm

e)

Volume of H2:

dV = 45.1

dV = (45.1*10^-3) L

f)

T = 22°C = 22+273 = 295K

g)

R from ideal gas

PV = nRT

R = PV/(nT)

R = (0.945263 *(45.1*10^-3))/(0.001810*295)

R = 0.07984

h)

error% = (0.082-0.07984)/(0.082) *100 = 2.64%

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