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Match the statement to the correct answer. (Some reagents can be used more than

ID: 547550 • Letter: M

Question

Match the statement to the correct answer. (Some reagents can be used more than once.) The flowchart along with the report sheets in experiment 5 should be very helpful A Barium Nitrate (Ba(NO3)2) B 6M Hydrochloric Acid (HcI) C oH, co32-, and PO43 D Zinc Nitrate (Z (NO3)2 E Lead Nitrate (0.1M Pb(NO3)3) F 0.1M sodium carbonate (Na2CO3) G Lead chloride (PbCl2(s)) H Disodium EDTA (Na2EDTA) I Silver Nitrate (AgNO3) J 1M ammonium hydroxide (NH40H) K Silver chloride (AgcI(s)) L Na+, No3, and NH4 M 6M Nitric Acid (HNO3) N Cation O Aluminum Nitrate (A(NO3)3) P Anion Q Colbalt Nitrate (Co(NO3)2) R NH4 (aq) and OH(aq) S None of the above This reagent is added to fresh solutions in test B2 where there was no reaction in test B1 salts containing these ions are often insoluble in water and form precipitates This reagent is added fresh samples in test A3 where there was no reaction in tests A1 or A2 Concentrated Ammonia (NH3) will combine with water to form these ions in solution In test B1 this is the first reagent added to the sample In test A2 you add this reagent to the test where a precipitate was formed

Explanation / Answer

I need the flow chart to answer the questions, specifically the ones which mention test tubes A1, A2, B1, B2, etc.

I will answer C and R unambiguously.

C. The listed anions are OH-, CO32- and PO43-. Salts of these anions, especially salkts with alkaline earth metals and transition metals are often insoluble in water. For example, Ca(OH)2 is sparingly soluble in water. CuCO3 and Mg3(PO4)2 are insoluble. Hence, the correct statement about these anions is “Salts containing these ions are often insoluble in water and form precipitates.”

R. A concentrated solution of ammonia, NH3 dissolves in water and forms a weak base. The reaction can be shown as below.

NH3(aq) + H2O(l) ----------> NH4+(aq) + OH-(aq)

Therefore, the correct statement is “Concentrated ammonia (NH3) will combine with water to form these ions in solution.”