Assume two connected vessels A and B at 25 degrees celsius separated by a valvve

Question

Assume two connected vessels A and B at 25 degrees celsius separated by a valvve. Vessel A contains 3.0 L of nitrogen gas at a pressure of 2.0 atm and the vessel B contains 4.0 L of oxygen gas at a pressure of 3.00 atm. If the valve is opened, what is the total pressure? Assume two connected vessels A and B at 25 degrees celsius separated by a valvve. Vessel A contains 3.0 L of nitrogen gas at a pressure of 2.0 atm and the vessel B contains 4.0 L of oxygen gas at a pressure of 3.00 atm. If the valve is opened, what is the total pressure?

Explanation / Answer

When the valve is opened , both the gase occupy both bulbs. thus the total volume = 3.0+ 4.0 = 7.0L

Now partial pressure of N2 after mixing

P1V1 = P2V2 at constant temperature

3.0L x 2.0 atm = P2 x 7.0L

Thus P2 of N2 = 6/7 = 0.8571 atm

Similarly partial pressure of O2 after mixing

P1V1 = P2V2 at constant temperature

4.0L x 3.0 atm = P2 x 7.0L

Thus P2 of N2 = 12/7 = 1.714 atm

Thus the total pressure after the valve is opened = PN2 + PO2 after mixing

= 0.8571 + 1.714 atm

= 2.5713 atm

  

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---