In peas, a gene controls flower color such that R =red and r = white. In an isolated pea patch, there were 84red flowers and 16 white flowers. Assuming Hardy-Weinbergequilibrium, what is the value of q for thispopulation? a) 0.80 b) 0.60 c) 0.40 d) 0.36 e) 0.64 f) 0.16 PLEASE SHOW YOUR WORK. In peas, a gene controls flower color such that R =red and r = white. In an isolated pea patch, there were 84red flowers and 16 white flowers. Assuming Hardy-Weinbergequilibrium, what is the value of q for thispopulation? a) 0.80 b) 0.60 c) 0.40 d) 0.36 e) 0.64 f) 0.16 PLEASE SHOW YOUR WORK.
Explanation / Answer
c) 0.40 Hardy-Weinberg equationis: p + q = 1 Given that there are 84red flowers and Red is dominant over white this is considered asp2 As there are 16 whiteflowers and white is recessive this is considered asq2. The population size is100 Now for solving forhardy-Weinberg equation: Frequency of dominant genotypeRR or p2 = number of RR individuals Population size = 84 100 p2 = 0.84 p = 0.91 Similarly the Frequencyof recessive genotype rr or q2 =number of rr individuals Population size = 16 100 q2 = 0.16 q = 0.4 p + q =1 0.84 + 0.16 =1