Consider the titration of H3C6H5O7 with NaOH. Let’s say that you need to add 0.0

Question

Consider the titration of H3C6H5O7 with NaOH. Let’s say that you need to add 0.0387 moles of NaOH in order for the indicator dye to change color. How many moles of H3C6H5O7 must you have had to start? Report answer to the correct sig figs. Do not provide units. Consider the titration of H3C6H5O7 with NaOH. Let’s say that you need to add 0.0387 moles of NaOH in order for the indicator dye to change color. How many moles of H3C6H5O7 must you have had to start? Report answer to the correct sig figs. Do not provide units.

Explanation / Answer

mol of base =0.0387

note that citric acid; H3C6H5O7 ; is triprotic therefore

H3A + 3NAOH = 3H2O + NaCitrate

H3C6H5O7 = 1/3* jmol of NAOH = 1/3*0.0387 = 0.0129 mol of citric acid

sig fig ---> 3; therefore, report 0.0129 mol of citric acid

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