Part B: Determining the pKa of an Unknown Acid pH of Unknown Acid: 302 Unknown #
ID: 560503 • Letter: P
Question
Part B: Determining the pKa of an Unknown Acid pH of Unknown Acid: 302 Unknown # | 4 3 lution PH (0.25 pt) Solution pH (0.25 pt) After 2.5 mL NaOH 355 After 5.0 mL NaOH After 17.5 mL NaOH 12.12 After 20.0 mL NaOH 2.4 342 After 7.5 mL NaOH 4 2After 22.5 mL NaOH 12.58 After 10.0 mL NaOH 4.53 After 12.5 mL NaOH 4 After 15.0 mL NaOH6 Observations (0.5 pt): The pH bo a big irceosed After 25.0 mL NaOH 12.6 After 27.5 mL NaOH | 12-ju After 30.0 mL NaOH/ 12.78 after i5mL ott, and the Solution 3. (1 pt) Determine the pKa of the unknown acid using your results from part B (Explain). Answer 4. (1 pt) Using Table 5.1 and your data from Part B, determine the identity of your unknown acid. Bubble in your answer at the right. A. KHP B. lactic acid C. acetic acid 5. (2 pts) Calculate the concentration of your unknown acid solution (show your work)?Explanation / Answer
Q3
get pKA from data in B:
pKa = from 50% equivalence point
pH = pKa at this point since A- = HA
pH = pKa + log(A-/HA) trnasforms to
pH = pKa
Vequivalence point --> between 12.5 and 15 mL -- <pH changes drastically
then
half equivalence point of V = 15 mL --> 7.5 mL
pH at V = 7.5 mL --> 4.22
pKa = pH = 4.22
Ka = 10^-pK = 10^-4.22 = 6.02*10^-5
Ka = 6.02*10^-5
Q4
identify unkown acid...
Ka lactic acid = too low
acetic acid = could be
KHP --> too high
therefore, the best fit is acetic acid
unkown acid cocentration
Ka = [H+][A-]/[HA]
6*10^-5 = x*X/(M-x)
x = [H+] = 10^-pH = 10^-3.02 = 0.000954
M = (0.000954)(0.000954)/(6*10^-5) + 0.000954
M = 0.0161 mol per liter