CHM 130LL Experiment 11 Name PRE-LAB QUESTIONS 1. Identify solute and solvent in

Question

CHM 130LL Experiment 11 Name PRE-LAB QUESTIONS 1. Identify solute and solvent in salt solution. solute: solvent: For a 12.6% NaCl solution, calculate the solubility of NaCl in 100 g of water. Calculation: 3. Which of the following solutions cannot dissolve any more solutes? i) dilute solution ii) unsaturated solution ii) saturated solution iv) none of these 4. Which of the following is a strong acid? ii) sulfurous acid iv) carbonic acid i) acetic acid iii) nitric acid Which of the following is an insoluble salt (-insoluble ionic compound)? See sol table given in the experiment 9 i) NaSO4 i) Ca(NO iv) co, iv) CO2 i) BaSO4 i) Na2SO4 Circle the electrolyte(s). (Hint: See Table 11.1 and solubility table.) KCla) aCls HCl)

Explanation / Answer

Ans.1. Solute = it is a solid substance that can be dissolved in a liquidl

Solvent = it is a liquid substance in which solute can be dissolve

For eg. NaCl is a solute and water is a solvent.

Ans 2. 12.6 % NaCl solution means 12.6 g of NaCl is dissolved in 100 g of water

Ans 3. (b) saturated solution means no more solute can dissolve at this point.

Ans 4 (c) Nitric acid, HNO3 is a strong acid.

Ans 5 (a) BaSO4 is an insoluble salt because solubility of sulphate decreases on moving down in a group of a periodic table.

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