For the following formula, CsHM, calculate the IHD and select all the types of u

Question

For the following formula, CsHM, calculate the IHD and select all the types of unsaturation that might be present in the molecule based on the IHD. Number The types of unsaturation that might be present O O no unsaturation; no multiple bonds or ring closings one double bond or one ring closing three double bonds or three ring closings; or two double bonds and one ring closing; or one double bond and two ring closings; or one triple bond and one double bond; or one triple bond and one ring clasing many possibilities; most likely a benzene ring O

Explanation / Answer

IHD = [2+2(C)-H]/2

IHD = [2+2(6)-14]/2 = [2+12-14]/2 = [14-14]/2 = 0/2 = 0

IHD = 0

Therefore, there is no unsaturation in this molecule.

so the option 1) no unsaturation, no multiple bonds or ring closings is correct

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