For the following formula, C7H1oNBr, calculate the IHD and select all the types

Question

For the following formula, C7H1oNBr, calculate the IHD and select all the types of unsaturation that might be present in the molecule based on the IHD. Number IHD = The types of unsaturation that might be present: O O no unsaturation; no multiple bonds or ring closings one double bond or one ring closing three double bonds; or three ring closings; or two double bonds and one ring closing; or one double bond and two ring closings; or one triple bond and one double bond; or one triple bond and one ring closing O many possibilities; most likely a benzene ring

Explanation / Answer

IHD = [2(C) + 2 + N - X - H]/2

C7H10NBr

IHD = [2(7)+2+1-1-10]/2 = [14+2+1-1-10]/2 = 6/2 = 3

Therefore, IHD = 3

Three double bonds; or three ring closings; or two double bonds and one ring closing; or one double bond and two ring closings; one triple bond and one double bond; or one triple bond and one ring closing is correct

option 3 is correct

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