Consider the following system at equilibrium where Ho-879 kJ/mol, and K.-1.20x10

Question

Consider the following system at equilibrium where Ho-879 kJ/mol, and K.-1.20x10-2 , at 500 K. PCls PCI3 ()+Cl2 (2) When 0.30 moles of PCls (g) are removed from the equilibrium system at constant temperature: the value of Kc A. increases B. decreases C. remains the same. the value of e A. is greater than Kc B. is equal to Kc C. is less than Kc. A. run in the forward direction to reestablish equilibrium. B. run in the reverse direction to reestablish equilibrium. C. remain the same. It is already at equilibrium. the reaction must: the concentration of PCI3 will: lA. increase B. decrease. C. remain the same. Submit Answer

Explanation / Answer

PCl5(g) ----------> PCl3(g) + Cl2(g)

kc = [PCl3][Cl2]/[PCl5]
the conc of PCl5 ( 0.3 moles) is removed from the equilibrium KC is decreases because of reverse reaction is favorable.
The value of Kc A. increases
The forward reaction is favorable.Kc>Qc
The value of Qc C.is less than KC
The reaction must: A. run in the forward direction to reestablish equilibrium.
the concentration of PCl3 will: A. increase

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