CHM2046C Vecabulary qule 122 ame: iba Alaualo 0.015 equilibrium 0.005-E.... 0- 5
ID: 573317 • Letter: C
Question
CHM2046C Vecabulary qule 122 ame: iba Alaualo 0.015 equilibrium 0.005-E.... 0- 5 10 15 20 time (sec) 1. The graph above shows what happens when 0.015 M HI is put in a reaction vessel at 300 c Initially only HI is present, but when HI,s with sufficient speed collide, they break apart to H and I. Sometimes two H's hit to form H2. Sometimes two I's form l2, and sometimes an H hits an I to form HI. Thereafter, H2, l2 and HI are all constantly being knocked apart to produce H and I atoms and recombining at random to form all 3 molecules. a) When the situation called equilibrium is reached, what has to happen somewhere in the vessel each time an HI molecule is knocked apart to prevent [HI] from decreasing further? b) Draw the arrow from the graph that shows what you have described in 1.a. anow ponwng nont or le c) What will [HI] be after one year? 2. A fuel cell does the chemistry below. 2H2(g) + O2(g) 2H20(1) a) Is the chemistry shown above an equilibrium or a preparation? (Circle one.) b) Circle the thing in the reaction above that gave you the answer to 2.a. c) How do the concentrations of the reactants change with time?Explanation / Answer
1a) At equilibrium, the reaction that occurs, HI <--->1/2 H2+1/2 I2
for every one molecule of HI broken apart ,one atom each of H and I collide with each other to form one HI.This way the rate of the breaking of HI and making of one HI takes place at constant rate.
rate of forward reaction=rate of reverse reaction
b) The concentration of HI decreases and the concentrations of H2 and I2 increases until they reach equilibrium.The flat portion of the graphs for [HI] vs time and for [H2],[I2] vs time represents the equilibrium concentrations of [HI] and [H2],[I2] respectively.
c)[HI] will be at its equilibrium concentration of 0.01M, if the physical conditions of temperature ,pressure remains the same