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I haven\'t done these calculations in some time. I tried #1 and #2, I dont think

ID: 574242 • Letter: I

Question

I haven't done these calculations in some time. I tried #1 and #2, I dont think #2 is correct. Please help. The more explaination, the better. Thank you

1) The formula weight of NaCl is 58.44 g/mol. How would you make 300 mL of a 0.75 M solution of NaCl?

(VxCxMW) 0.3L x 0.75moles/L x 58.44g/mole = 13.149g

2) If your bottle of solid NaCl stated that the salt was only 90% pure, how much would you now have to weigh out to make 300 mL of a 0.75 M solution?

(VxCxMW) 0.3L x (0.90% x 0.75moles/L) x 58.44g/mole = ?

3) Starting with your 0.75 M solution of NaCl, how would you make 100 mL of a 25 mM solution of NaCl?

4) You are given a 10% (w/v) solution of NaCl – what is the concentration in Moles/L?

5) You have been given a solution of ATP of unknown concentration. You take 1 mL of the solution, and dilute to a final volume of 50 mL. The absorbance of this dilute solution at 259 nm is 0.570. What is the concentration of the original solution:

a) In mmoles/liter?

b) In mg/ml?

The Molar extinction coefficient of ATP is 15,400 l/mol cm.

The formula weight of ATP is 507.18 g/mole

Explanation / Answer

1.

300 mL of a 0.75 M solution

So, moles of NaCl = 0.75 M x 300 mL
                              = 0.75 M x 0.3 L
                              = 0.225 moles of NaCl

Molar mass of NaCl = 58.4 g/mol
So, 1 mole of NaCl = 58.4 g
or, 0.225 moles of NaCl = 0.225 x 58.4 g
                                       = 13.14 g

So, you now have to weigh out 13.14 g of solid NaCl and dissolve in 300 mL of solvent to make a 0.75 M solution.

2.

300 mL of a 0.75 M solution

So, moles of NaCl = 0.75 M x 300 mL
                              = 0.75 M x 0.3 L
                              = 0.225 moles of NaCl

Molar mass of NaCl = 58.4 g/mol
So, 1 mole of NaCl = 58.4 g
or, 0.225 moles of NaCl = 0.225 x 58.4 g
                                       = 13.14 g

Now, the solid NaCl is 90% pure, which means

     90 g of NaCl is present in 100 g of the solid NaCl
or, 1 g of NaCl is present in (100/90) g of the solid NaCl
or, 13.14 g of NaCl is present in 13.14 x (100/90) g of the solid NaCl
or, 13.14 g of NaCl is present in 14.6 g of the solid NaCl

So, you now have to weigh out 14.6 g of solid NaCl and dissolve in 300 mL of solvent to make a 0.75 M solution.

3.

We know that

M1 V1 = M2 V2
or, 0.75 M x V1 = 25 mM x 100 mL
or, 0.75 M x V1 = 0.025 M x 100 mL
or, 0.75 x V1 = 2.5 mL
or, V1 = (2.5 / 0.75) mL = 3.33 mL

Hence, take 3.33 mL of 0.75 M NaCl and mark the water to 100 mL.

4.

10% (w/v) solution of NaCl means

10 g of NaCl in 100 mL of solution
or, 100 g of NaCl in 1000 mL of solution

Now,
Molar mass of NaCl = 58.4 g/mol
So, 58.4 g of NaCl = 1 mol
or, 1 g of NaCl = (1 / 58.4) mol
or, 100 g of NaCl = (100 / 58.4) mol = 1.71 mol

So, the concentration in Moles/L = 1.71 mol/L