The preparations of two aqueous solutions are described in the table below. For
ID: 574498 • Letter: T
Question
The preparations of two aqueous solutions are described in the table below. For equilibrium. You can leave out water itself Write the chemical formulas of the species that will act as acids in the 'acids row, the formulas of the species that will act as bases in the bases row, and the formulas of the species that will act as neither acids nor bases in the 'other row You will find it useful to keep in mind that NH, is a weak base db acids 1.9mol of HCius added to L of 1.0 M NH solution 0.2mol of KOH is added to 1.0L of a solution that is 0.9 M in both NH, and NH,Br adds: basesExplanation / Answer
HCl + NH3 ------------> NH4Cl
initially 1.9 mol 1 mol 0
after reaction 0.9 mol 0 1 mol
Acid is HCl and Base is NH3 in this reaction
KOH + NH3 + NH4Br ---------> NH4OH + KBr
initially 0.2 mol 0.9 mol 0.9 mol 0 0
after rxn 0 0.9 mol 0.7 mol 0.2 mol 0.2 mol
Acid is NH4Br and Base is KOH in this reaction