Part 2 calculate the equilibrium constant for the reaction Be sure to answer all

Question

Part 2 calculate the equilibrium constant for the reaction
Be sure to answer all parts. The equilibrium lies to the right in the reaction below. Following the curved arrows, complete the equation to show the products formed. Identify the acid, base, conjugate acid, and conjugate base. Part 1t a x CHs view structure Conjugate acid Conjugate base Part 2 out of 2 Calculate the equilibrium constant for the reaction. Refer to a table of pk, values in your book Enter your answer in scientific notation x 10 Next part 27 MacBook Ai 0 F7 F8 8 3

Explanation / Answer

CH3SH (aq) <----> CH3S- (aq) + H+(aq) , Ka = 4 x 10^ -11 .........................eq(1)

(CH3)3COH (aq) <---> (CH3)3CO-(aq) + H+ (aq) , Ka = 3 x 10^ -17   ..............................eq(2)

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Now eq(1) - eq(2)   gives us required eq

Ka = Ka in eq(1) / Ka in eq(2)    = ( 4 x 10^ -11) / ( 3 x 10^ -17) = 1.33 x10^ 6

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