MindTap Cengage Lea eMatch The FollowingAc .Teche mistry question Mastering Engi
ID: 575244 • Letter: M
Question
MindTap Cengage Lea eMatch The FollowingAc .Teche mistry question Mastering Engineering Cengage Che X > d Not secure ng·cengage.com/static/nb/ui/index.html?nbld-737561 &nbNodeld;=278405395&eISBN-97813056575714;parentld-278405423 MINDTAP From Cenza Massood Sattari 13.4 Mastery Due l oday at 8 AM CSI Late submission until Jan 31 at 8 AM CSI is allowed, with a one time 10% penalty to submitted score. 1. Calculate Osmoti... Use the Refcrenees to access important valnes if needed for this question. 2. Molar Mass from... Match the following aqueous solutions with the appropriate letter from the column on the right. Assume complete dissociation of electrolytes. 3. Calculations Usi... 4. BP/FP Calculatio... 1.0.24 m KOH 2. 9.5×10-in Cr(NO3)3 3. 0.21 FeSO4 4. 0.44 mEthylene glycol (nonelectrolyte) A. Lowest freezing point B. Second lowest freezing point C. Third lowest freezing point D. Highest freezing point 5. Calculate Mw Sol 6. Arrange Aqueou... 2 req Question Question Question Submit Answer A-Z 7. BP/FP Calculatio... 2 req Submit 6. Arrange Aqueous Electrolytes in Order of BP/FP:This is group attempt 3 of 5 Current score Autosaved at 3:13 AM Back Next 6258.75 pts (71.43 %) Type here to search 3:14 AM 1/29/2018 1]Explanation / Answer
The freezing point depression is given as : i . kf . m
where i = vant hoff's factor
kf = freezing constant (same for all)
m = molality
So finally the depression depends on i and m
maximum the depression , lowest will be the freezing point .
So here :
1) 0.24 m KOH
= 2 x kf x 0.24
= 0.48 kf
2)9.5 x 10-2 m Cr(NO3)3
= 4 x Kf x 9.5 x 10-2
= 0.38 Kf
3) 0.21 m FeSO4
= 2 x kf x 0.21
= 0.42 Kf
4) 0.44 m ethylene glycol
= 1x kf x 0.44
= 0.44 Kf
So now the ranking will be :
1 : A
2 : D
3 : C
4 : B