Please this is two pictures for lab ex so check #2 and 3 Thank you EXPERIMENT 3
ID: 579924 • Letter: P
Question
Please this is two pictures for lab ex so check #2 and 3Thank you
EXPERIMENT 3 WEIGHT ANALYSIS OF A COPPER OXIDE 158 6.19 Data and Calculations Mass of empty test tube Mass of the copper oxide before you heated Mass of the copper after 20 minutes of heating Mass of the copper after 30 minutes of total heating: Final mass of the copper metal powder: Mass that disappeared during the heating What element or compound disappeared -55-070 6x1son from the copper oxide during heating? Moles of copper in the pellet: Moles of oxide that escaped Empirical formula of the initial copper oxide: 35 Show calculation Mass percentage of copper in copper oxide Show calculation: 1: 09 Experin..t 31 Weight Analysis of a Copper Caid,
Explanation / Answer
The electron configuration for copper is 1s2 2s2 2p6 3s2 3p6 4s1 3d10. Copper is an electropositive element, i.e it it donates electrons to other atoms. copper can donate either one or two electrons. The electronic configuration of Oxygen is 1s22s22p4. so it can accept two electrons.so it can accept two electrons.
hence two possibilies are CuO and Cu2O.
2. weight of iron oxide = 1.996 gm and weight of iron present = 1.396
moles of iron = mass/ atomic weight = 1.396/56=0.025
mass of oxide = mass of iron oxide- mass of iron present = 1.996-1.396 =0.6 gm
moles of O in the oxide= 0.6/16= 0.0375
molar rati of Fe: O= 0.025:0.0375, dividng by 0.0125, the ratio becomes 0.025/0.0125 :0.0375/0.0125= 2:3
The compound formed is Fe2O3. This is the molecilar formula of the compound.