Physics Projectile Help!!!!! Please Explain Each step and do not use hand writin
ID: 585484 • Letter: P
Question
Physics Projectile Help!!!!! Please Explain Each step and do not use hand writing (if you use hand-writing, please write clearly) Thank you
The pitcher in a slow-pitch softball game releases the ball at a point 3.0 ft above ground level. A stroboscopic plot of the position of the ball is shown in the figure below, where the readings are 0.25 s apart and the ball is released at t = 0.
The pitcher in a slow-pitch softball game releases the ball at a point 3.0 ft above ground level. A stroboscopic plot of the position of the ball is shown in the figure below, where the readings are 0.25 s apart and the ball is released at t-0 10 I=0 10 40 20 x (ft) 30 (a) What is the initial speed of the ball? (b) What is the speed of the ball at the instant it reaches its maximum height above ground level? (c) What is that maximum height? ftExplanation / Answer
Total time of flight (above release point) = 5*(0.250) = 1.25 s
Horizontal range (above release point) = 40 ft
Horizontal speed = Vox = 40/1.25 = 32 ft/s ANSWER (b)
Time to reach max height = t = 1.25/2 = 0.625 s
Initial Vertical speed = (speed lost in t) = Voy = gt = 32.2*(0.625) = 20.125 ft/s { g = 32.2 ft/s^2 }
Initial speed of ball = sqrt(Voy^2 + Vox^2) = sqrt(20.125^2 + 32^2) = 37.8 ft/s ANSWER (a)
Max height of ball (above release point) = 1/2gt^2 = (0.5)*(32.2)*(0.625)^2 = 6.29 ft
Max height of ball above ground level = 3.0 + 6.29 = 9.29 ft ANSWER (c)