A. Specific Heat of a Metal A.1 Identification Number First run .104 Mass of met
ID: 587643 • Letter: A
Question
A. Specific Heat of a Metal A.1 Identification Number First run .104 Mass of metal A.2 Mass of Stryofoam calorimeter A.3 Mass of Stryofoam calorimeter and water A.4 Temperature of boiling water bath A.5 Initial temperature of water in calorimeter A.6 Final temperature of water and metal in calorimeter l. 9 100'C Calculations A.7 Temperature change AT (C) for water A.8 Heat calories used to warm water Show calculations A.9 Heat calories lost by the metal object A. 10 Temperature change AT (C) for metal A.11 Specific heat of the metal (cal/g) Show calculations)Explanation / Answer
Mass of water mw = mass of Styrofoam and water - mass of Styrofoam
= 51.879 - 1.890
= 49.989 g
Specific heat capacity of water Cpw = 4.184 J/g°C
Since the temperature of metal increases from 20°C to 25°C
Heat gained by water Q = mw x Cpw x (T2-T1)
= 49.989 g x 4.184 J/g°C x (25-20)°C
= 1045.76988 J x 1 calories/4.184J
= 249.945 calories
Heat lost by metal = heat gained by water = 249.945 calories
Temperature change of metal = final temperature of metal - initial temperature of metal
= 25 - 100
= - 75°C
Negative sign shows that the heat is removed from the metal
Specific heat of metal = Q/(mass of metal x temperature change)
= 249.945 cal / (4.640g x 75°C)
= 0.7182 cal/g-C