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I\'m trying to figure out part 3 ton.com/16235 9.67 out of 10 12/13/17 This is a

ID: 588029 • Letter: I

Question





I'm trying to figure out part 3

ton.com/16235 9.67 out of 10 12/13/17 This is a Mixed question/ It is worth 1 point /You have unlimited attempts/There is no attempt penalty 03 Question (1 point) e See page 382 The process illustrated below takes place at constant pressure. (The figure is not drawn to scale; the molecules are actually much, much smaller relative to the container.) Reaction SO 3rd attempt See Periodic Table See Hint Part 1 (0.3 point) Write a balanced equation for the process. (Do not include states of matter.) He 250, +02-2503

Explanation / Answer

3)

Given
Hof(SO2(g)) = -296.83 KJ/mol
Hof(O2(g)) = 0.0 KJ/mol
Hof(SO3(g)) = -395.72 KJ/mol

Balanced chemical equation is:
2 SO2(g) + O2(g) ---> 2 SO3(g)

Ho rxn = 2*Hof(SO3(g)) - 2*Hof( SO2(g)) - 1*Hof(O2(g))
Ho rxn = 2*(-395.72) - 2*(-296.83) - 1*(0.0)
Ho rxn = -197.78 KJ

this is when 2.00 moles of SO3 is reacting
so,
for 4.00 moles of SO3,
Ho rxn = 2*(-197.78) = -395.56 KJ

Answer: -395.56 KJ