Part C A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4
ID: 588714 • Letter: P
Question
Part C
A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 525 mL of a solution that has a concentration of Na+ ions of 0.800 M ?
Express your answer to three significant figures and include the appropriate units.
Resources previous l 2 of 13 | next Chapter 9 Homework : Ion Concentration Submit My Answers Give Up ± Ion Concentration Correct lon concentration refers to the molar concentration of an ion in solution. It may be identical to, or greater or less than, the mclan concentration of the compound containing the ion that was used to make the solution. For soluble salts, the mclarity of a particular ion is equal to the molarity of that compound times the subscript for that ion. For example, 1 M of AIC13 is 1 M in Al and 3 M in C1-. 1 M of (NH4)2S04 is 2 M in NH+ and 1 M in SO42 Part B If CaCl2 is dissolved in water, what can be said about the concentration of the Ca2+ ion? Hints It has the same concentration as the Cl ion. Its concentration is half that of the Cl ion. Its concentration is twice that of the Cl ion ts concentration is one-third that of the CI ion. Submit My Answers Give Up Correct Part C will be needed to A scientist wants to make a solution of tribasic sodium phosphate, NaPO4, for a laboratory experiment. How many grams of Na PO produce 525 ml. of a solution that has a concentration of Na+ ions of 0.800 M Express your answer to three significant figures and include the appropriate units. Hints mass of Na PO4-42 Submit My Answers Give Up Incorrect: Try Again Provide Feedback ContinueExplanation / Answer
no of moles of Na^+ = molarity * volume in L
= 0.8*0.525 = 0.42 moles of Na^+
3 moles of Na^+ ions produced from 1 moles of Na3Po4
0.42 moles of Na^+ ions produced from = 1*0.42/3 = 0.14 moles of Na3Po4
mass of Na3PO4 = no of moles * gram molar mass
= 0.14*164 = 22.96g of Na3Po4 >>>>>>answer