ANALYSIS Solution Standardization Standardized concentration of NaOH solution: 1

Question

ANALYSIS Solution Standardization Standardized concentration of NaOH solution: 1Trial 2 M ge standardized concentration of NaOH solution:04M Avera Determination of Citric Acid Trial 2 Moles of citric acid Trial 1 Moles of NaOH: moles Relationship between Moles of Citric Acid and Moles of NaOH Number of moles of NaOH per mole of citric acid: Number of moles of citric acid per mole of NaOH the reaction between NaOH and citric acid; - Number of acidic hydrogen atoms per molecule of citric acid: Number of molecules of citric acid per acidic hydrogen atom: Determination of Beverage Sample Trial 1Trial 2 Moles of NaofH consumed: moles moles moles Moles of citric acid neutralized: Molarity of citric acid in beverage sample: Average M of beverage: moles LM % Concentration by mass: (assume density of 1.00 gmL) Average % concentration:

Explanation / Answer

Following reaction takes place between citric acid and NaOH

C6H8O7 + 3NaOH --> NaC6H5O7 + 3H2O

1 mole of citric acid = 3 moles of NaOH

moles of citric acid per mole naOH= 1/3.

= 0.33 moles

No of acidic hydrogens per mole citrc acid= no of moles of NaOH nuetralize by 1 mole CItric acid

By srtoichiometry 3 moles of NaOH can be nyuetrtalized by 1 mole of citric acid

so No of acidic hydrogens per mole citrc acid=3

and

No of citrc acid per acidic hydrogens = 1/No of acidic hydrogens per mole citrc acid

=1/3

=0.33

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---