I need help with the Height of Integration and Product Distribution. H NMR spect

Question

I need help with the Height of Integration and Product Distribution. H NMR spectrum of 2-bromohexane (The M arkovnikov ad dition product) 1,79 2-bromohexane PPM 'H NMR spectrum of 1-bromohexane (The anti-Markovnikov addition product) 1.31 1.29 3.51 1.291.2 4 3 2 PPM B) HNMR Analysis (representative spectrum will be distributed by instructor in which case product ratio may not agree with those from GC analysis of your Signals for Hydrogen Atoms Attached to Carbon Bearing the Bromine 2-Bromohexane: Chemical Shift (ppm) Multiplicity of Signal Height of Integration Step (mm) 1-Bromohexane: 3.51 Chemical Shift (ppm) Multiplicity of Signal Height of Integration Step (mm) Product Distribution: Proportion of Product formed by lonic Mechanism Proportion of Product fromed by Free Radical Mechanism % 164

Explanation / Answer

In the spectrum integrations are not mentioned, but

for 2- bromohexane, the integration comes for one proton, which is attached to bromine, where as in1-bromo hexane, the integration comes for 2 protons, the height of integration doubles when compared to 2-bromohexane

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---