ANODE Mass of Cu wire before electrolysis Mass of Cu wire after electrolysis Mas

Question

ANODE Mass of Cu wire before electrolysis Mass of Cu wire after electrolysis Mass of Cu lost by electrode Is the mass lost by this electrode equal to the gain in mass by the other electrode? Is this what you -748 1-669 -79 expeet? Explain. Moles of Cu lost by electrode Calculation Moles of e required Calculation Calculated value for the Faraday Calculation % Error Calculated value for Avogadro's number Calculation % Error Which electrode, if any, gives you better value for the Faraday and Avogadro's number? How can you explain this?

Explanation / Answer

Q1

mass is lost by anode and gained in the cathode

a.

Mol of Cu ost:

mass of Cu initial - mass of Cu final = 0.79 g

mol = mass/MW = 0.79/63.5 = 0.012440 mol of Cu

b)

1 mol of Cu = 2 mol of e-

0.012440 mol of Cu = 2*0.012440 = 0.02488 mol of e-

1 mol of e- = 96500 C (Farday)

0.02488 mol of e- = x

x = 0.02488*96500

x = 2400.92 C

d)

Avogrados no:

Charge used / charge applied --> Na (data is not added here)

Na number is approx = 6.022*10^23

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