MasteringChemistry: Chapter 11 Homework -Google Chrome Secure l https://session.
ID: 592965 • Letter: M
Question
MasteringChemistry: Chapter 11 Homework -Google Chrome Secure l https://session.masteringchemistry.com/myctitemview?assi grmentproblemibanos Chapter 11 Homework Core Chemistry Skill Calculating Molarity or Volume of an Acid or Base in us ±Core Chemistry Skill. Calculating Molanty or Volume of an Acid or Base in Titration previous 10 of 10 retum to assignment , she put 755 mL fthe acid n Ache mist needs to determine the concentration of a solution of nitric acid H es a flask along with a few drops of indicator. She then slowly adds 0 turns pink, indicating the equivalence point of the titration She notes that 285 mL of Ba(OH0)2 was needed to each the equivalence point 800 MBa(OH)2 to the fask undi the solutior ome Learning Goal: ents To calculate the concentration of a solution using acid-base titration data Solution map In an acid-base titration, an acid (or base) of known concentration is added to a base (or acid) of unknown concentration until the number of moles of H and OH are equal, a condition called the In this titration, the concentration of base is known and can be used to calculate the unknown acid concentration concentration of base moles of base- moles of acid-, concentration of acid -t ings equivalence point Since you know the number of Part A moles of H (or OH that you added you can determine the number of moles of OH (or H') in the unknown solution Htow many moles of BalOH), are presen ih 285 ml of l), Express your answer with the appropriate units. For example, a solution containing 1 mol of HoSO, contains 2 mol of ionizable hydrogen atoms and would therefore require 2 mol of NaOH for neutralization Hints My Answers Give Up Part B 24 PRExplanation / Answer
M = 0.800 M
volume = 285 mL = 0.285 L
use:
number of mol = Molarity * volume
= 0.800 M * 0.285 L
= 0.228 mol
Answer: 0.228 mol