Minions have two hair styles, sprout and spread out. Spread out (O) is dominant

Question

Minions have two hair styles, sprout and spread out. Spread out (O) is dominant to sprout (o). A chubby female minion with two eyes and spread out hair mates with a thin, one eyed male that also has spread out hair. Both minions are heterozygous for hair style. The male minion is homozygous dominant for number of eyes and the female minion is heterozygous for body size (chubby).

a. What are the genotypes of these parents?

b. They have 32 children, how many do you expect to be genotype ccEeOo?

c. They have 32 children, how many do you expect to have the phenotype chubby, two eyed, and spread out hair?

Explanation / Answer

Let chubby be C and thin be represented by c. Also let one eye male be E and two eyed by e.

a) Genotype of Female minion CceeOo

Genotype of Male minion ccEEOo

b) Chances of having cc = 1/2; Chances of having Ee = 1; Chances of having Oo = 1/4

So, chances of having ccEeOo = 1/2*1*1/4= 1/8

1/8 of 32 = 4 (children are expected to having the given genotype out of 32)

c) Phenotype Chubby should be C_ = 1/2; phenotype two eyed is "e". No child can have this phenotype. So, the phenotype chubby, two eyed and spread out hair is impossible.

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