Consider the following equation: 2N2O (g) ?? 2N2 (g) + O2 (g) a. At 25?C, the Kc
ID: 600076 • Letter: C
Question
Consider the following equation: 2N2O (g) ?? 2N2 (g) + O2 (g)a. At 25?C, the Kc value for this reaction is 7.3 x 1034. Is the forward or reverse reaction favored? Justify your answer.
b. At 25?C, the concentrations for this reaction were [N2O] = 0.55 M, [N2] = 0.12 M, and [O2] = 0.89 M. Is this reaction at equilibrium? If no, which direction will the reaction need to progress to reach equilibrium?
Explanation / Answer
at 25 C the given Kc >1 and is highly positive so the forward reaction is highly favourable. b> at this conc the calculated K = 0.0423 this is far less than the Kc value .hence the system is not in equilibrium to reach the eq this reaction shud go in fwd reaction