Consider the following reaction: S2O8^(2-)(aq) + 3 I-(aq) --->2 SO4^(2-)(aq) + I

Question

Consider the following reaction: S2O8^(2-)(aq) + 3 I-(aq) --->2 SO4^(2-)(aq) + I^(3-)(aq) (a) The rate law for this reaction is first order in S2O82-(aq) and first order in I-(aq). What is the rate law for this reaction? **(a) Rate = k [S2O82-(aq)] [I-(aq)] b) Rate = k [S2O82-(aq)]2 [I-(aq)] c) Rate = k [S2O82-(aq)] [I-(aq)]2 d) Rate = k [S2O82-(aq)]2 [I-(aq)]2 e) Rate = k [S2O82-(aq)] [I-(aq)]3 f) Rate = k [S2O82-(aq)]4 [I-(aq)] (b) If the rate constant for this reaction at a certain temperature is 0.00795, what is the reaction rate when [S2O82-(aq)] = 0.0474 M and [I-(aq)] = 0.0671 M? Rate = ____________ M/s. (c) What is the reaction rate when the concentration of S2O82-(aq) is doubled, to 0.0948 M while the concentration of I-(aq) is 0.0671 M? Rate = _____________ M/s

Explanation / Answer

k[S2O8-2][I-]

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