Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid (C7
ID: 615962 • Letter: M
Question
Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid (C7H6O3) with methanol (CH3OH) C7H6O3 + CH3OHExplanation / Answer
the molar mass of each species are: Mr C7H6O3 = 138.123 g/mol Mr C8H8O3 = 152.1494 g/mol Mr CH3OH = 32.04 g/mol you have 6.252g of salicylic acid to be reacted with excess of methanol thus the moles of salicylic acid are moles salicylic acid = 6.252 g / 138.123 g/mol = 0.045 mol the balanced reaction is : C7H6O3 + CH3OH --> C8H8O3 + H2O because the mole ration between C7H6O3 and C8H8O3 is 1:1 thus 0.045 mol of C7H6O3 will theoretically produce 0.045 mol of C8H8O3 too, and the mass of C8H8O3: mass C8H8O3 = 0.045 mol x 152.1494 g/mol = 6.887 grams remember that this is the theoretically mass of C8H8O3, because the yield of the reaction is 68.63% so the actual mass of C8H8O3 tha has been produced is: actual mass C8H8O3 = 68.63% x 6.887 grams = 4.726 gr