I\'m really stuck on how to approach this problem. Please show work Model 1-Assu

Question

I'm really stuck on how to approach this problem. Please show work Model 1-Assume that each molecule is a cube with the sides of length "t". Find: volume of a molecule of cetyl alcohol (v=t^3) number of molecules in the monolayer (N=V/v) Number of moles in the monolayer (n=m/242.50) number of molecules in 1 mole; avogadro's number (N0=N/n) Model 2- Assume each molecule is a rectangle with the longer sides five times the shorter side. The longer side of the rectangle will be the monolayer thickness, t. Find: volume of a molecule of cetly alcohol [v=t(t/5)(t/5)] number of molecules in the monolayer (N=V/v) Number of moles in the monolayer (n=m/242.50) avogadro's number (N0=N/n)

Explanation / Answer

formula of cetyl alcohol is CH3(CH2)15OH or C16H34O.hence,the molecular weight is given by 12*16+34*1+16=242 which is approx 242.50........Now,it is assumed that each molecule is a cube with side "t".we know that volume of a cube is given by (side)^3 hence,volume of 1 cetyl alcohol molecule is t^3.....number of molecules in the monolayer is given by (total volume)/(volume of each molecule)= V/v....number of moles is given by (mass of monolayer)/(molecular weight)=m/242.50.......similarly in model 2 volume occupied by each molecule is =length*base*height=t*(t/5)*(t/5)......number of molecules in the monolayer is V/v and number of moles=m/242.50....plz rate :)

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